Giải phương trình: \(|7-2x|=|5-3x|+|x+2|\)   (1)
Ta có
(1)    \(\Leftrightarrow |(5-3x)+(x+2)|=|5-3x|+|x+2|\)
         $\Leftrightarrow [(5-3x)+(x+2)]^2=(|5-3x|+|x+2|)^2$
         \(\Leftrightarrow (5-3x)(x+2)=|5-3x|.|x+2|\)
         \(\Leftrightarrow (5-3x)(x+2)\geq 0 \\\Leftrightarrow -2\leq x\leq \frac{5}{3}\)

Vậy PT đã cho có nghiệm $-2\leq x\leq \frac{5}{3}$
Trong các phương pháp giải phương trình chứa dấu giá trị tuyệt đối có phương pháp vẽ bảng xét dấu các biểu thức trong dấu giá trị tuyệt đối. Nhưng mà hình như không phải bài nào cũng giải được phải không ạ ?VD : Giải phương trình: |7−2x|=|5−3x| |x 2|Em gi –  gavinwalker1994 10-11-14 09:31 AM

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