Giải các phương trình:
$a)  \frac{12x}{x-4} - \frac{3x^2}{x+4} = \frac{384}{x^2 - 16}   ;          b) 2x^3 - 3x^2 + 6x + 4 = 0 $
$c) 2x^3+3x^2-x-1=0 ;    d) 6x^4 + 19x^3 - 7x^2 -26x + 12 = 0$.

Đáp số:
a) S = {$8$}.         b) S = {$-\frac{1}{2} $}             c) S = $\left\{ {-\frac{1}{2}; -\frac{1}{2}(1+ \sqrt{5} ) ;  -\frac{1}{2}(1- \sqrt{5} )  } \right\}$
d) S = $\left\{ {-3;\frac{1}{2}; -\frac{1}{3}(1+ \sqrt{13} ) ; -\frac{1}{3}(1- \sqrt{13} ) } \right\}$
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