|
|
|
|
Giải các bất phương trình :
$\begin{array}{l}
1)\,\left( {4{x^2} - 16x + 7} \right){\log _2}\left( {x - 3} \right) > 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\\
2)\,{\log _5}\left[ {\left( {{2^x} - 4} \right)\left( {{x^2} - 2x - 3} \right) + 1} \right] > 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)
\end{array}$
|
Giải bất phương trình :
$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{6^{\log _6^2x}} + {x^{{{\log }_6}x}} \le 12\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)$
|
|
|
Đăng bài 26-04-12 08:54 AM
|
|
|
Đăng bài 25-04-12 11:34 AM
|
Đăng bài 25-04-12 09:17 AM
|
Đăng bài 24-04-12 01:40 PM
|
Đăng bài 24-04-12 11:19 AM
|
Đăng bài 23-04-12 02:07 PM
|