Cho hai tam giác vuông cân OABOAB có chung đỉnh O sao cho O nằm trên đoạn thẳng AB và nằm ngoài đoạn thẳng AB.gọi G,G lần lượt là trọng tâm các tam giác OAA,OBB.Chứng minh rằng GOG là tam giác vuông cân

 Xét phép quay Q tâm O góc quay 900 ta có ngay :
ΔOBB=Q900O(ΔOAA)G=Q900O(G)
^GOG=900OG=OG
Vậy ta được ΔGOG là tam giác vuông cân

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