Tam giác ABC cân, cạnh đáy BC có phương trình: x+3y+1=0. Cạnh bên AB có phương trình: x – y + 5 = 0. Đường thẳng chứa cạnh AC đi qua điểm M(-4;1). Tìm tọa độ đỉnh C.
Nhận thấy điểm có tọa độ M(-4;1)thỏa mãn các phương trình đường thẳng BCAB\Rightarrow  BCAB đi qua M.Theo giả thiết AC cũng đi qua M\Rightarrow  ba cạnh \Delta ABC đồng quy tại M,vô lý. Bài toán không xác định

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