Giải các phương trình sau đây:
1)   $\log_2(\log_3(\log_2x))=1$
2)   $(\sqrt{5+2\sqrt{6} } )^{\sin x}+(\sqrt{5-2\sqrt{6} } )^{\sin x}=2$
3)   $4\sqrt{3}\sin x\cos x\cos2x=\sin 8x $
$1$) $log_2(log_3(log_2x))=1\Leftrightarrow log_3(log_2x)=2$
$\Leftrightarrow log_2x=9\Leftrightarrow x=2^9$
$2$) Đặt $t = \,{\left( {\sqrt {5 + 2\sqrt 6 } } \right)^{{\mathop{\rm sinx}}}}>0$
ta được pt $t+\frac{1}{t}=2$
$\Leftrightarrow t=1\Leftrightarrow sinx=0\Leftrightarrow x = k\pi $
$3)$ $4\sqrt 3 \sin {\rm{x}}\cos x\cos 2x = \sin 8x$
$
 \Leftrightarrow \sqrt 3 \sin 4x = 2\sin 4x\cos 4x\\$

$\Leftrightarrow\left[\begin{array}{I} \sin 4x=0\\\cos 4x=\frac{\sqrt{3}}{2}\end{array}\right.$

 $\Leftrightarrow \left[ \begin{array}{l}
x = k\frac{\pi }{4}  (k\in Z)\\
x =  \pm \frac{\pi }{24} + k\frac{\pi }{2}  (k\in Z)
\end{array} \right.
$

Thẻ

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