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Ta có
\mathop {\lim }\limits (n^{2}+\frac{1}{n})(\frac{3-2n}{n^{3}-2})
=\mathop {\lim }\limits \frac{n^{3}+1}{n}.\frac{3-2n}{n^{3}-2}
=\mathop {\lim }\limits \frac{n^{3}(1+\frac{1}{n^{3}})}{n}.\frac{n(\frac{3}{n}-2)}{n^{3}(1-\frac{2}{n^{3}})}
=\mathop {\lim }\limits(1+\frac{1}{n^{3}})\frac{\frac{3}{n}-2}{1-\frac{2}{n^{3}}}
=(1+0)\frac{0-2}{1-0}=-2
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