Cho hàm số $y = \frac{3x - 4}{x - 2}$. Tìm điểm thuộc $ (C)$ cách đều $2$ đường tiệm cận.
Giả sử $M(x;y)$ thuộc đồ thị.
Khoảng cách từ M đến tiệm cận đứng và tiệm cận ngang bằng nhau, tức là:
$\left| {x - 2} \right| = \left| {y--3} \right| \Leftrightarrow \left|{x - 2} \right| = \left| {\frac{{3x - 4}}{{x - 2}} - 2} \right| \Leftrightarrow \left| {x - 2} \right| = \left| {\frac{x}{{x - 2}}} \right|$
$\Leftrightarrow \frac{x}{{x - 2}} =  \pm \left( {x - 2} \right) \Leftrightarrow \left[ \begin{array}{l}
x = 1\\
x = 4
\end{array} \right.$

Vậy 2 điểm cần tìm là:  ${{\rm{M}}_{\rm{1}}}\left( {{\rm{ 1}};{\rm{1}}} \right){\rm{;}}\,{\rm{ }}{{\rm{M}}_{\rm{2}}}\left( {{\rm{4}};4} \right)$

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