Giải phương trình
$2\sin^{2}x+(1-\sqrt{3})\sin x.\cos x+(1-\sqrt{3})\cos ^{2}x=1$

$$2\sin^{2}x+(1-\sqrt{3})\sin x.\cos x+(1-\sqrt{3})\cos ^{2}x=1  (1)$$
+) Với $\cos x=0$ hay $x=\frac{\pi}{2}+k\pi$, thay vào phương trình $(1)$ta được:
$2.0+(1-\sqrt{3}).0+(1-\sqrt{3}).0=1$ (sai)
 Vậy $\cos x=0$ không thỏa mãn phương trình $(1)$
 +) Với $\cos x\neq0$ hay $x\neq\frac{\pi}{2}+k\pi$, chia 2 vế của phươg tnrình $(1)$ cho $\cos^{2}x$ ta được:
 $$2\tan^{2}x+(1-\sqrt{3})\tan  x+(1-\sqrt{3})=\frac{1}{\cos^{2}x}$$
 $\Leftrightarrow 2\tan^{2}x+(1-\sqrt{3})\tan x +(1-\sqrt{3})=1+\tan^{2}x $
 $\Leftrightarrow \tan^{2}x+(1-\sqrt{3})\tan x -\sqrt{3}=0$
 $\Leftrightarrow \left[ \begin{array}{l}\tan x = -1\\\tan x = \sqrt{3}\end{array} \right.$

 $\Leftrightarrow \left[ \begin{array}{l}x = -\frac{\pi}{4}+k\pi\\x = \frac{\pi}{3}+k\pi\end{array} \right.      k\in Z$
 Các nghiệm này thỏa mãn điều kiện $\cos x\neq 0$

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