Chứng minh hệ thức: 1C1n+C2nC3n+...+(1)kCkn=(1)kCkn1
Sử dụng công thức     Ckn=Ckn1+Ck1n1 ở vế trái, ta có:
                                       C1n=C1n1+C0n1
                                       C2n=C2n1+C1n1
                           (1)kCkn=(1)k(Ckn1+Ck1n1)
Suy ra:            VT=(1)kCkn1    (đpcm).

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