Tìm miền xác định các hàm số sau :
$a)$ $y = \sqrt {\cos x - 1} $               $ b$) $y = \sqrt {x + \sqrt {{x^2} - x + 1} } $
                          Giải  
Ta có:
$a)$ Hàm số xác định khi $cosx   – 1 \geq 0 \Leftrightarrow cos \geq 1$
Mà ta có : $cosx \leq 1, \forall x \Rightarrow cosx = 1 \Rightarrow x = k2\pi $
$b$) $y = \sqrt {x + \sqrt {{x^2} - x + 1} } $
Nhận xét :$ x^2 – x + 1 >0  \forall  x,$         vì : $\triangle = -3 < 0$
Hàm số xác định khi $x + \sqrt {{x^2} - x + 1}  \geq 0$

 $x < 0 \Rightarrow x + \sqrt {{x^2} - x + 1} $ $ = \frac{{{x^2} - x + 1 - {x^2}}}{{\sqrt {{x^2} - x + 2
} - x  }} > 0$
$ \Rightarrow $ D = R

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