Đáp án mới nhất

10

Giải phương trình: $\cos [\frac{\pi }{2}\cos (x-\frac{\pi }{4})]=\frac{\sqrt{2} }{2} $
0

a) Tìm tất cả các nghiệm nguyên của phương trình sau: $\cos \left[ {\frac{\pi }{8}\left( {3x - \sqrt {9{x^2} + 160x + 800} } \right)} \right] = 1$b) Biết rằng $\sin 15^0= \frac{\sqrt{6 } -\sqrt{2 } }{4}$. Tính các tỉ số lượng giác của...
7

a/ $\frac{sin^22x-4sin^2x}{sin^22x+4sin^2x-4}+1=2tan^2x$b/ $sin^4x+cos^4x=\frac{7}{8}cot(x+\frac{\pi}{3}).cot(\frac{\pi}{6}-x) $c/ $\frac{sin^4\frac{x}{2}+cos^4\frac{x}{2}}{1-sin x}-tan^2x.sin x=\frac{1+sin x}{2}+tan^2 x$
7

a/ $\frac{sin^22x-4sin^2x}{sin^22x+4sin^2x-4}+1=2tan^2x$b/ $sin^4x+cos^4x=\frac{7}{8}cot(x+\frac{\pi}{3}).cot(\frac{\pi}{6}-x) $c/ $\frac{sin^4\frac{x}{2}+cos^4\frac{x}{2}}{1-sin x}-tan^2x.sin x=\frac{1+sin x}{2}+tan^2 x$
7

a/ $\frac{sin^22x-4sin^2x}{sin^22x+4sin^2x-4}+1=2tan^2x$b/ $sin^4x+cos^4x=\frac{7}{8}cot(x+\frac{\pi}{3}).cot(\frac{\pi}{6}-x) $c/ $\frac{sin^4\frac{x}{2}+cos^4\frac{x}{2}}{1-sin x}-tan^2x.sin x=\frac{1+sin x}{2}+tan^2 x$
5

Giải phương trình lượng giác:a) $\frac{tanx.cos3x+2cos2x-1}{1-2sinx}=\sqrt{3}(sin2x+cosx)$b) $\frac{sin3x-cosx}{cos2x}=\sqrt{2}\frac{tan^2x+tan2x-1}{1-tan^2x}$
3

Giải phương trình: $cosx+cos2x+cos4x+ cos3x+cos5x=\frac{-1}{2}$
6

$sin(\frac{3\pi }{10}-\frac{x}{2})=\frac{1}{2}sin(\frac{\pi }{10}+\frac{3x}{2})$
11

$cos\frac{4x}{3}=cos^2x$
8

1.$ cotx - tanx + 4sin2x = \frac{2}{sin2x} $2.$ cos^{4} + sin^{4} + cos(x-\frac{\pi }{4}).sin(3x-\frac{\pi }{4}) - \frac{3}{2} $3.$ \frac{(1+ sinx+cos2x).sin(x+\frac{\pi }{4})}{1+tanx} = \frac{1}{\sqrt{2}}cosx $4.$...
8

Cho phương trình: $\sin 2x+\sin x-\cos x =\frac{1}{2}$Tìm góc A,B,C của tam giác ABC là nghiệm của phương trình
5

1.$5sinx-2=3.(1-sinx)tan^{2}$2.$2sin3x-\frac{1}{sinx}=2cos3x+\frac{1}{cosx}$
8

1.$5sinx-2=3.(1-sinx)tan^{2}$2.$2sin3x-\frac{1}{sinx}=2cos3x+\frac{1}{cosx}$
2

Giải các pt:a) $6\sin x-\frac{5\sin 4x.\cos x}{2\cos 2x}=2\cos^{3} x$b) $\cos 7x-\sin 5x=\sqrt{3}(\cos 5x-\sin 7x)$c) $8\sin x=\frac{\sqrt{3}}{\cos x}+\frac{1}{\sin x}$d) $\sin x+\sin^{2} x\cos x+2\sin x\cos^{2} x-2\cos x=0$
3

Giải các pt:a) $6\sin x-\frac{5\sin 4x.\cos x}{2\cos 2x}=2\cos^{3} x$b) $\cos 7x-\sin 5x=\sqrt{3}(\cos 5x-\sin 7x)$c) $8\sin x=\frac{\sqrt{3}}{\cos x}+\frac{1}{\sin x}$d) $\sin x+\sin^{2} x\cos x+2\sin x\cos^{2} x-2\cos x=0$
3

Giải các pt:a) $6\sin x-\frac{5\sin 4x.\cos x}{2\cos 2x}=2\cos^{3} x$b) $\cos 7x-\sin 5x=\sqrt{3}(\cos 5x-\sin 7x)$c) $8\sin x=\frac{\sqrt{3}}{\cos x}+\frac{1}{\sin x}$d) $\sin x+\sin^{2} x\cos x+2\sin x\cos^{2} x-2\cos x=0$
3

Giải các pt:a) $6\sin x-\frac{5\sin 4x.\cos x}{2\cos 2x}=2\cos^{3} x$b) $\cos 7x-\sin 5x=\sqrt{3}(\cos 5x-\sin 7x)$c) $8\sin x=\frac{\sqrt{3}}{\cos x}+\frac{1}{\sin x}$d) $\sin x+\sin^{2} x\cos x+2\sin x\cos^{2} x-2\cos x=0$
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