Cho $a,b,c,d>0$ thỏa mãn $a^2+b^2+c^2+d^2=4$. Chứng minh:
$\frac{1}{3-abc}+\frac{1}{3-bcd}+\frac{1}{3-cda}+\frac{1}{3-dab}\leq2$
Đây là 1 BĐT tương đối khó của Phạm Kim Hùng. Không làm được hay đọc lời giải không hiểu là điều bình thường.
Bạn có thể tham khảo lời giải dưới đây.
bạn này cũng đọc Sáng tạo bđt của anh Hùng à –  annguyenkha98 23-08-14 03:35 PM

Bạn cần đăng nhập để có thể gửi đáp án

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