$H=\frac{\sqrt{10-6\sqrt{2}}-\sqrt{10+6\sqrt{2}}}{\sqrt{5-\sqrt{7}}} - \sqrt{9-2\sqrt{20}} $
bài này có j mà khó –  ๖ۣۜTQT☾♋☽ 21-08-17 02:11 AM
Bài khó thế –  nguyenconghoanganh02 20-08-17 08:07 PM
4Ta có$:(\sqrt{10-6\sqrt{2}}-\sqrt{10+6\sqrt{2}})^2=20-2\sqrt{(10-6\sqrt{2})(10+6\sqrt{2})}=20-2\sqrt{100-72}=20-4\sqrt{7}$
$\Rightarrow \sqrt{10-6\sqrt{2}}-\sqrt{10+6\sqrt{2}}=-\sqrt{20-4\sqrt{7}}$
Ta có:
$H=-\frac{\sqrt{4(5-\sqrt{7})}}{\sqrt{5-\sqrt{7}}}-\sqrt{2^2-2.2.\sqrt{5}+(\sqrt{5})^2}=-\sqrt{4}-\sqrt{(\sqrt{5}-2)^2}=-2-\sqrt{5}+2=-\sqrt{5}$
à à r bác –  ๖ۣۜTQT☾♋☽ 24-08-17 01:00 AM
Vẫn chưa được? Sau chỗ "Ta có: H = ... (ở dưới mẫu ấy)" –  Thanh Long 23-08-17 08:51 AM
vâng bác................ –  ๖ۣۜTQT☾♋☽ 23-08-17 01:11 AM
Hãy chỉnh lại lời giải, vì H có giá trị âm. –  Thanh Long 22-08-17 08:13 PM

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