Cho $y=x^3-3x^2+2$  (C)
Tìm trên (C) 2 điểm pb M, N scho tiếp tuyến tại M, N //, đồng thời MN cắt Ox, Oy tại A, B pb và $AB=\sqrt{37}$
$y'=3x^2-6x$
$M(a;a^3-3a^2+2), N(b;b^3-3b^2+2) (a \neq b)$
tiếp tuyến tại M, N // => $y'(M)=y'(N)$
=> $3a^2-6a=3b^2-6b$
<=> $a=b(L)$ hoặc $a+b=2(N)$
=> $N(2-a;-a^3+3a^2-2)$
MN có vtcp $\overrightarrow{v}(2-2a;-2a^3+6a^2-4)$
=> MN có vtpt $\overrightarrow{n}(2a^3-6a^2+4;2-2a)$
MN qua $M(a;a^3-3a^2+2)$, vtpt $\overrightarrow{n}$
=> $(a^3-3a^2+2)x+(1-a)y-a^3+3a^2-2=0$
$A=MN$  $ \Lambda$  $  Ox$ => $y_A=0$ => $x_A=1$
$B=MN $  $\Lambda$  $ Oy$ => $x_B=0$ => $y_B=a^2-2a-2$
$AB=\sqrt{37}$ => $AB^2=37$
=>  $1+(a^2-2a-2)^2=37$
=> $a=4$ hoặc $a=-2$
+) $a=4$ => $M(4;18), N(-2;18)$
+)$a=-2$ => $M(-2;18), N(4;18)$

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