\begin{cases}\sqrt[3]{4(x^{3}+y^{3})}+\sqrt[3]{2x^{2}-3xy^{2}+2y^{3}}=2x+y\\ 4\sqrt{x(y^{2}+3)}+4y\sqrt{y}=3y^{2}+4x+2y+3 \end{cases}
đề này thầy mk cho –  ­ 30-03-16 06:03 PM
đề này lấy đâu ra vậy :D –  tran85295 29-03-16 07:03 PM
uk khó thật –  ­ 29-03-16 06:52 PM
:(( cái này dã man thật :| chắc mk chịu -__- I'm so sorry. But I can't –  ☼SunShine❤️ 29-03-16 06:45 PM
cám ơn :) mà mình k còn đủ sò để treo rồi –  ­ 29-03-16 06:41 PM
Cách này đơn giản hơn nek:
Pt (2) tg đg:$(y^2+3-4\sqrt{x(y^2+3)}+4x)+(2y^2+2y-4y\sqrt{y})=0$
$\Leftrightarrow (\sqrt{y^2+3}+2\sqrt{x})^2+2y(\sqrt{y}-1)^2=0$ mà đk là $y\geq 0$
Đến đây thì dễ r!  
Suy ra nghiệm r ms dùng cái (1) để loại!
Còn cách nữa là đánh giá pt (1)! chắc cho lằng nhằng là như z!

Bạn cần đăng nhập để có thể gửi đáp án

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