Chứng minh rằng $\frac{\sqrt{1+x^{3}+y^{3}} }{xy}$ + $\frac{\sqrt{1+x^{3}+z^{3}} }{xz}$ + $\frac{\sqrt{1+y^{3}+z^{3}} }{yz}$ $\geq$ 3$\sqrt{3}$
Cauchy cái trên tử của từng phân thức là ra bạn ak –  Dark 24-10-15 11:44 PM
Áp dụng bđt:$a^{3}$+$b^{3}$$\geq$ab(a+b)
đpcm$\Leftrightarrow$$\Sigma $$\sqrt{\frac{xyz+x^{3}+y^{3}}{(xy)^{2}}}$$\geq$$\sqrt{x+y+z}$.$\Sigma$$\sqrt{\frac{1}{xy}}$$\geq$$\sqrt{3}$.3$\sqrt[3]{\frac{1}{xyz}}$=3$\sqrt{3}$
dấu''=''xra $\Leftrightarrow$x=y=z=1
siêu thế –  nguyenthiquynhphuong 16-02-16 06:15 PM
chăm j đâu.thích thì lm thui.ai chẳng z..... –  nhung 15-02-16 10:45 PM
chăm ghê :D –  Confusion 15-02-16 10:43 PM

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