cho $P(x)=(1+x)+ 2.(1+x)^{2}+3.(1+x)^{3}+...+20.(1+x)^{20}$
                 $=a_{0}+a_{1}.x+a_{2}.x^{2}+...+a_{20}.x^{20}$
Tìm $a_{15}$
Dẽ thấy hệ số của $x^{15}$ chỉ chứa trong $15(x+1)^{15} +...+20(x+1)^{20}$

Áp dụng công thức số hạng tổng quát $C_n^k a^k .b^{n-k}$ trong khai triển $(a+b)^n$

Khi đó hệ số lần lượt là $15C_{15}^1 ;\ 16C_{16}^{15};\ 17C_{17}^{15};\ ...;\ 20C_{20}^{15}$

Cộng hết lại là xong

Bạn cần đăng nhập để có thể gửi đáp án

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