Bài $1 : \cos^3x . \cos 3x + \sin^3 x.\sin3x = \cos^3 4x$
Bài $2 : \cos^3x.\sin3x + \sin^3 x.\cos 3x= \sin^3 4x$
Thanks mọi người
1)
pt$\Leftrightarrow \frac{1}{4}(3cosx+cos3x)cos3x+\frac{1}{4}(3sinx-sin3x)sin3x=cos^34x$
$\Leftrightarrow 3(cosx.cos3x+sinx.sin3x)+cos^23x-sin^23x=4cos^34x$
$\Leftrightarrow 3cos2x+cos6x=4cos^34x$
$\Leftrightarrow 3cos2x+4cos^32x-3cos2x=4cos^34x$
$\Leftrightarrow cos^32x=cos^34x\Leftrightarrow cos2x=cos4x\Leftrightarrow \left[ \begin{matrix} 2x=4x+k2\pi\\ 2x=-4x+k2\pi\end{matrix}{} \right.\Leftrightarrow \left[ \begin{matrix}x=-k\pi\\ x=\frac{k\pi}{3}  \end{matrix}{} \right.(k\in Z)$
không có gì ^^ –  Wind 06-08-14 07:28 PM
thank nhá –  HIHI 06-08-14 04:38 PM
2)
pt$\Leftrightarrow \frac{1}{4}(3cosx+cos3x)sin3x+\frac{1}{4}(3sinx-sin3x)cos3x=sin^34x$
$\Leftrightarrow \frac{3}{4}sin3x.cosx+\frac{1}{4}sin3x.cos3x+\frac{3}{4}sinx.cos3x-\frac{1}{4}sin3x.cos3x=sin^34x$

$\Leftrightarrow 3(sin3x.cosx+cos3x.sinx)=4sin^34x$
$\Leftrightarrow 3sin4x-4sin^34x=0\Leftrightarrow sin12x=0\Leftrightarrow x=\frac{k\pi}{12}$  $(k\in Z)$
nếu bạn biết cách gộp nghiệm thì gộp lại sẽ ra như đáp án của mình.Nhưng nên chọn cách hạ bậc để đơn giản hóa pt :) –  Wind 06-08-14 07:28 PM
Bài này mình giải được 3 nghiệm nà... mình giải máy tính phương trình bậc 3 –  HIHI 06-08-14 05:30 PM
kcg,bài 1 mình vẫn đang làm^^ –  Wind 06-08-14 01:20 PM
thanks Gió –  HIHI 06-08-14 01:13 PM
Bài 1 thế nào nhỉ ? Gió ..

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