$\left ( 1+\sin 2x\right )$$\left ( \sin x+\cos x\right )$=$\sin x$+3$\cos x$
$pt<=>(1+sin2x)(sinx+cosx)=sinx+cosx+2cosx$

$<=>(1+sin2x-1)(sinx+cosx)=2cosx$

$<=>2sinx.cosx(sinx+cosx)=2cosx$

$<=>cosx(sin^2x+sinx.cosx-1)=0$

$<=>cosx(cos^2x+sinx.cosx)=0$

$<=>cos^2x(sinx+cosx)=0$

$<=>\sqrt2cos^2x.sin(x+\frac{\pi}4)=0$

$XONG$
Dung thi nhan V va vote up cho mk nhe –  ♥♥♥ Panda Sơkiu Panda Mập ♥♥♥ 11-04-14 09:17 PM
$\Rightarrow sinx+cosx+2sin^2x.cosx+2cos^2x.sinx=sinx+3cosx$
dễ thấy $cosx=0$ là nghiệm của pt$\Rightarrow x=\frac{\pi }{2}+k\pi$
với  $cosx\neq 0$
pt$\Rightarrow 2tan^2x+2tanx=2(tan^2x+1)$
đơn giản rồi bạn giải tiếp nhé
à quên vậy còn 1 nghiệm cosx=o nữa –  m_internet001 11-04-14 09:18 PM
cosx=0 van la mot nghiem cua pt –  ♥♥♥ Panda Sơkiu Panda Mập ♥♥♥ 11-04-14 09:17 PM
sai roi nhe. cos = 0 thi dong dau tien thu gon lai se la 0=0 –  ♥♥♥ Panda Sơkiu Panda Mập ♥♥♥ 11-04-14 09:16 PM
dấu suy ra thứ 2 là chia 2 vế cho cos^3 nhé –  m_internet001 11-04-14 09:16 PM

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