$1)sinx+cosxsin2x+\sqrt3cos3x=2(cos4x+sin^3x)$

$2)\sqrt3cos5x-2sin3xcos2x-sinx=0$

$3)5(sinx+\frac{cos3x+sin3x}{1+2sin2x})=3cos2x$
hỏi. mà tóm lại là lười. k mún nghĩ à. –  ♥♥♥ Panda Sơkiu Panda Mập ♥♥♥ 15-02-14 10:04 PM
Mục đích hỏi hay post chơi –  Dép Lê Con Nhà Quê 15-02-14 10:02 PM
Câu 3 điều kiện tự làm

ta có $\cos 3x +\sin 3x = 4(\cos^3 x -\sin^3 x) -3(\cos x -\sin x) =(\cos x -\sin x )(1+2\sin 2x)$

Bài toán đưa về $5(\sin x +\cos x -\sin x) =3\cos 2x =3(2\cos^2 x -1)$ quá dễ
Câu 2

$\sqrt 3 \cos 5x−2\sin 3x \cos 2x−\sin x=0$

$\Leftrightarrow \sqrt 3 \cos 5x -\sin 5x -\sin x -\sin x = 0$

$\Leftrightarrow \sqrt 3 \cos 5x -\sin 5x =2\sin x$ chia 2 vế cho 2 thì quá cơ bản, Xong
Câu 1: 

$\sin x + 2\cos^2 x \sin x+ \sqrt 3 \cos 3x = 2\cos 4x + 2\sin^3 x$

$\Leftrightarrow \sin x + 2\sin x (\cos^2 x -\sin^2 x) + \sqrt 3 \cos 3x = 2\cos 4x $

$\Leftrightarrow \sin x + 2\sin x \cos 2x + \sqrt 3 \cos 3x = 2\cos 4x $

$\Leftrightarrow \sin x + \sin 3x -  \sin x  + \sqrt 3 \cos 3x = 2\cos 4x $ 

Xong

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