$2cos3x +\sqrt{3}sin x +cosx=0$
$\Leftrightarrow \sqrt{3}/2.\sin x+1/2.\cos x=-\cos 3x$
$\Leftrightarrow \cos (x-\pi/3)=\cos (3x-\pi)$
$\Leftrightarrow x-\pi/3=3x-\pi+2k\pi\Leftrightarrow x=\pi/3-k\pi$
hoặc $x-\pi/3=-3x+\pi+2k\pi\Leftrightarrow x=\pi/3+k\pi/2$
sai công thức ở dưới rồi pải ko? –  daica28thienthien 29-07-19 04:14 PM
bai lam dung roi mà .chap nhan dap an giup mình voiclick vao chu V thoi (giup minh) –  Вő˚CĦĬĈŊ♂ 20-06-13 04:09 PM
co van de gi? –  Вő˚CĦĬĈŊ♂ 20-06-13 01:46 PM
$\cos(\frac{\pi}{3}-x)=\cos(3x \pi)$ –  iamshant1207 20-06-13 11:55 AM
huynh ơi cho em hỏi -cos3x=cos(3x-pi)=cos(3x+pi) 
nếu em thế cos(3x+pi) vào đây thì phương trình trên là đáp án khác ( đúng hok ạ) 
(em không biết sự dụng đường tròn lượng giác mong huynh giúp giùm ) cám ơn 
poor guy ^^ –  mrpoor1994 13-12-14 08:19 PM
hjxpó tay lun –  Bi L-Lăng cmn N-Nhăng 12-12-14 11:04 PM

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