Giải PT: $2 \log_{2+\sqrt{3}}  x+\sqrt{x^2+1} + \log_{2-\sqrt{3}}  \sqrt{x^2+1} -x = 3$
Dễ thấy PT có nghĩa với mọi $x$
Sử dụng 2 đẳng thức sau : $ (x+\sqrt{x^2+1})( \sqrt{x^2+1} -x) =1 $ và $ (2+\sqrt{3})(2-\sqrt{3}) =1$
Suy ra $ \log_{2+\sqrt{3}}  (x+\sqrt{x^2+1}) = \log_{2-\sqrt{3}}  (\sqrt{x^2+1}-x$)
PT đã cho $\Leftrightarrow 3 \log_{2+\sqrt{3}}  (x+\sqrt{x^2+1}) =3 $
$\Leftrightarrow \log_{2+\sqrt{3}}  (x+\sqrt{x^2+1}) =1 $
$\Leftrightarrow x+\sqrt{x^2+1} = 2+\sqrt{3} $
Chuyển $x$ sang phải bình phương là xong

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