Giải và biện luận phương trình:
$(a^2+a-2)x^2+(2a^2+a+3)x+a^2-1=0.$
Xét  $a^2+a-2=0   \Rightarrow \left[ {\begin{matrix}a=1 \\a=-2 \end{matrix}} \right.$      
   Nếu $a=1$. PT $\Leftrightarrow 6x=0  \Leftrightarrow   x=0$.
   Nếu $a=-2$. PT $\Leftrightarrow 9x+3=0\Leftrightarrow x=-\frac{1}{3} $

Xét  $a^2+a-2 \neq 0 $ tức là $   a \neq 1$  và  $a \neq -2$,  phương trình đã cho là phương trình bậc hai có biệt thức   $\Delta = (5a+1)^2 \geq 0$.
    $a \neq  -\frac{1}{5}    \Rightarrow $   Phương trình có hai nghiệm      $x_1=-\frac{a-1}{a+2};     x_2= -\frac{a+1}{a-1}  $.
    $a=-\frac{1}{5}      \Rightarrow  $  Phương trình có nghiệm kép       $x=\frac{2}{3} $.

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