xet ngu giac
ABCND co
\widehat{BAD}=\widehat{BCD}=\widehat{BND}=90^0=>ngu giac nay noi tiep duong tron duong kinh BD tam
I la trung diem
BD va
AC goi C(a;-5-2a)=>I(\frac{a-4}2;\frac{3-2a}2) ma IA=IN=>(a+4)^2+(15+2a)^2=(a-14)^2+(11-2a)^2
=>a=\frac{76}{140} (so xau nen ban tu tinh nha)=>C;I
goi B theo hai an thuoc duong tron tam I(co mot pt )
=> toa do cua M,D =>M,N.D thang hang (pt thu hai)(khong can dung BN vuong goc voi DM vi da sd o tren)
tu hai pt => toa do cua B