Đáp án mới nhất

0

1) Giải các phương trình sau:a)$(x+2)^3+2(x^3+4x^2+x-1)+6=3x^3+20x+20$b)$x^3(x-1)+4x^2(x^2-2x+8)=8x^4+x^3$c)$\frac{x^5(x-6)}{x^4-x+1}=-5$
1

1) Giải các phương trình sau:a)$(x+2)^3+2(x^3+4x^2+x-1)+6=3x^3+20x+20$b)$x^3(x-1)+4x^2(x^2-2x+8)=8x^4+x^3$c)$\frac{x^5(x-6)}{x^4-x+1}=-5$
1

1) Giải các phương trình sau:a)$(x+2)^3+2(x^3+4x^2+x-1)+6=3x^3+20x+20$b)$x^3(x-1)+4x^2(x^2-2x+8)=8x^4+x^3$c)$\frac{x^5(x-6)}{x^4-x+1}=-5$
2

1) Giải các phương trình sau:a)$(x+2)^3+2(x^3+4x^2+x-1)+6=3x^3+20x+20$b)$x^3(x-1)+4x^2(x^2-2x+8)=8x^4+x^3$c)$\frac{x^5(x-6)}{x^4-x+1}=-5$
1

Đặt t = $ \frac{x}{(x^{2} - x + 1 )}$ . Tính theo t giá trị của biểu thức A = $ \frac{x^{2}}{(x^{4} + x^{2} + 1 )} $
4

$x \in \mathbb R$$x^{4}-13x^{3}+39x^{2}+13x-40=0$
14

$2x^{2}-3x+2=x\sqrt{3x-2}$Xem thêm:Mời mọi người tham gia cuộc thi do các Admin tổ chức CLICK!
3

(x−2)(√3x+1−1)=3x
3

$2(\sqrt{1+x}+\sqrt{1-x})+\sqrt{1-x^2}=\frac{x^4}{32}-x^2+5$ giải đến đoạn này r mà giải tiếp ko ra nghiệm??:$(\frac{a}{\sqrt{2}}+\sqrt{2})^2=(\frac{x^2}{4\sqrt{2}} -2\sqrt{2})^2$vs $a=\sqrt{1+x}+\sqrt{1-x}$
5

$2(\sqrt{1+x}+\sqrt{1-x})+\sqrt{1-x^2}=\frac{x^4}{32}-x^2+5$ giải đến đoạn này r mà giải tiếp ko ra nghiệm??:$(\frac{a}{\sqrt{2}}+\sqrt{2})^2=(\frac{x^2}{4\sqrt{2}} -2\sqrt{2})^2$vs $a=\sqrt{1+x}+\sqrt{1-x}$
3

$1.\sqrt{x^{2}-2x+5}-\sqrt{x^{2}-6x+10}=\sqrt{5}$$2.2(1-x)\sqrt{x^{2}+2x-1}=x^{2}-2x-1$$3.\sqrt{3x+1}-\sqrt{2-x}=\frac{4x-1}{3}$$4.\sqrt{2x-1}+x^{2}-3x+1=0$$5.3(2+\sqrt{x-2})=2x+\sqrt{x+6}$$6.\sqrt{x^{2}+12}+5=3x+\sqrt{x^{2}+5}$7.Tìm m để pt có 2...
12

$1.\sqrt{x^{2}-2x+5}-\sqrt{x^{2}-6x+10}=\sqrt{5}$$2.2(1-x)\sqrt{x^{2}+2x-1}=x^{2}-2x-1$$3.\sqrt{3x+1}-\sqrt{2-x}=\frac{4x-1}{3}$$4.\sqrt{2x-1}+x^{2}-3x+1=0$$5.3(2+\sqrt{x-2})=2x+\sqrt{x+6}$$6.\sqrt{x^{2}+12}+5=3x+\sqrt{x^{2}+5}$7.Tìm m để pt có 2...
9

$1.\sqrt{x^{2}-2x+5}-\sqrt{x^{2}-6x+10}=\sqrt{5}$$2.2(1-x)\sqrt{x^{2}+2x-1}=x^{2}-2x-1$$3.\sqrt{3x+1}-\sqrt{2-x}=\frac{4x-1}{3}$$4.\sqrt{2x-1}+x^{2}-3x+1=0$$5.3(2+\sqrt{x-2})=2x+\sqrt{x+6}$$6.\sqrt{x^{2}+12}+5=3x+\sqrt{x^{2}+5}$7.Tìm m để pt có 2...
7

$1.\sqrt{x^{2}-2x+5}-\sqrt{x^{2}-6x+10}=\sqrt{5}$$2.2(1-x)\sqrt{x^{2}+2x-1}=x^{2}-2x-1$$3.\sqrt{3x+1}-\sqrt{2-x}=\frac{4x-1}{3}$$4.\sqrt{2x-1}+x^{2}-3x+1=0$$5.3(2+\sqrt{x-2})=2x+\sqrt{x+6}$$6.\sqrt{x^{2}+12}+5=3x+\sqrt{x^{2}+5}$7.Tìm m để pt có 2...
8

$1.\sqrt{x^{2}-2x+5}-\sqrt{x^{2}-6x+10}=\sqrt{5}$$2.2(1-x)\sqrt{x^{2}+2x-1}=x^{2}-2x-1$$3.\sqrt{3x+1}-\sqrt{2-x}=\frac{4x-1}{3}$$4.\sqrt{2x-1}+x^{2}-3x+1=0$$5.3(2+\sqrt{x-2})=2x+\sqrt{x+6}$$6.\sqrt{x^{2}+12}+5=3x+\sqrt{x^{2}+5}$7.Tìm m để pt có 2...
12

$1.\sqrt{x^{2}-2x+5}-\sqrt{x^{2}-6x+10}=\sqrt{5}$$2.2(1-x)\sqrt{x^{2}+2x-1}=x^{2}-2x-1$$3.\sqrt{3x+1}-\sqrt{2-x}=\frac{4x-1}{3}$$4.\sqrt{2x-1}+x^{2}-3x+1=0$$5.3(2+\sqrt{x-2})=2x+\sqrt{x+6}$$6.\sqrt{x^{2}+12}+5=3x+\sqrt{x^{2}+5}$7.Tìm m để pt có 2...
1

Giải phương trình: $3x^{3}-4x^{2}-19x-\sqrt{-3x^{2}+6x+1} x(x+1)+24=0$
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