Cho hình vuông ABCD có cạnh 8cm và hình vuông DEFG có cạnh 4cm xếp cạnh nhau như hình vẽ dưới đây. Hãy tính diện tích tam giác ACF?

ABCDEFG8cm4cm



ABCDEFGH8cm4cm

Kéo dài BC và GF cắt nhau tại H

Ta có dt(ACF) = dt(ABHG) - dt(ABC) - dt(AGF) - dt(CHF)

Mà:

    dt(ABHG) = (8 + 4) x 8 = 96 cm2

    dt(ABC) = 8 x 8 : 2 = 32 cm2

    dt(AGF) = (8 + 4) x 4 : 2 = 24 cm2

    dt(CHF) = 4 x 4 : 2 = 8 cm2

Vậy: dt(ACF) = 96 - 32 - 24 -8 = 32 cm2

Đáp số: 32 cm2

Bạn cần đăng nhập để có thể gửi đáp án

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