1) giải pt $36x^2+\frac{1}{x^2}+21x+\frac{7}{2x}-18=0$
2)tìm nghiệm nguyên của pt $(x+y)^2=(x-1)(y+1)$
3)cho pt $x^2-2(m-1)x-3=0$ , (m là tham số). Tìm m để pt có hai nghiệm phân biệt x1 và x2 sao cho$\left| {x1} \right|+\left| {x2} \right|=4\sqrt{3}$ 
$pt\Leftrightarrow (6x)^2+2.6x.1/x+1/x^2-12+21x+7/2x-18=0$$\Leftrightarrow (6x+1/x)^2+7/2.(6x+1/x)-30=0$
đặt 6x+1/x=t
khi đó $t^2+7/2t-30=0\Rightarrow t=4 hoặc t=-15/2$
th1
$6x+1/x=4=>x=...$
th2
$6x+1/x=-15/2=>x=...$

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