a) cos6x+sin6x=2(cos8x+sin8x)
b) 2sin3xcos2x+cosx=0
c) cos2x+5=2(2xcosx)(sinxcosx)
d) 82cos6x+22sin3sin3x62cos4x1=0
e) 1tanx+cot2x=2(cosxsinx)cotx1
xin lỗi muội nha!tối qua anh ko lên được! –  ♫ξ♣ __Kevil__♣ ζ♫ 03-07-16 08:12 AM
zxczxczxc lm hộ cái đi –  Đức Anh 02-07-16 10:30 PM
ko biết làm mà bày đặt kêu dễ. sàm vl –  zxczxczxc 02-07-16 09:47 PM
ryo chế giỏi thì lm giúp em đi –  Đức Anh 02-07-16 09:33 PM
biết làm thì đăng đáp án đi –  zxczxczxc 02-07-16 08:27 PM
dễ hơn quy định tự làm cho thông minh đi e :D –  AKIRA 02-07-16 07:16 PM
uk đồng ý luôn –  ♫ξ♣ __Kevil__♣ ζ♫ 02-07-16 05:14 PM
làm hộ cái nhá –  Băng Băng 02-07-16 05:00 PM
mình xin chỗ này nhá !mọi người hết sức bình tĩnh ! –  ♫ξ♣ __Kevil__♣ ζ♫ 02-07-16 04:51 PM
http://d0.violet.vn//uploads/resources/present/1/445/950/preview.swf
Câu c) vd 3 trang 2
Câu d) bài số 15 trang 5.
click V nha –  tasfuskau 03-07-16 09:18 AM
b)
http://diendantoanhoc.net/topic/87893-gi%E1%BA%A3i-ph%C6%B0%C6%A1ng-trinh-2sin3x-cos2xcosx-0/
click V nha –  tasfuskau 03-07-16 09:18 AM
  

   Câu a) trước nhá :
   
   Phương trình tương đương : (cos2x)3+(sin2x)3=2((cos4x)2+(sin4x)2)
       <=>(cos2x+sin2x)(cos4xcos2xsin2x+sin4x)=2((cos4x+sin4x)24cos4xsin4x
       <=>(sin2x+cos2x)23sin2xcos2x=2((12sin2xcos2x)24sin4xcos4x
       <=>13sin2xcos2x=28sin2xcos2x+4sin4xcos4x
       <=>4(sinxcosx)45(sinxcosx)2+1=0
       <=>(sinxcosx)2=1 hoặc (sinxcosx)2=14
   TH1: sinxcosx=1<=>12sin2x=1<=>sin2x=2 (loại)
   TH2: sinxcosx=1<=>12sin2x=1<=>sin2x=2 (loại)
   TH3: sinxcosx=12<=>sin2x=1<=>2x=Π2+k2Π<=>x=Π4+kΠ
   TH4: sinxcosx=12<=>sin2x=1<=>2x=Π2+k2Π<=>x=Π4+kΠ

   Chúc muội học tốt !


    
cho nó đẹp ca –  ๖ۣۜJinღ๖ۣۜKaido 02-07-16 09:13 PM
xài \pi ấy π –  ๖ۣۜJinღ๖ۣۜKaido 02-07-16 09:12 PM

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