$\begin{cases}y^2(y^2+1)^2+(x^2+3x+2)(x+2)=2(y^3+y)(x+2)\sqrt{x+1} \\ [\sqrt[4]{x^2-2y^2+4}-\sqrt{x^4+3}+y^2-1][1+y^2\sqrt{x^2+2y^2}-\sqrt{x^2+y^2}(1+\sqrt{x^2+y^2+1})]=x+1-y^2 \end{cases}$

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omd :)) rối mắt –  Hoàng Yến 06-06-16 09:35 PM
Mình đăng cho các bạn tham khảo thôi, gg là ra đáp án –  Dark 06-06-16 09:10 PM
http://dethi.violet.vn/present/show/entry_id/11676184
Tự làm chứ link thì lên gg tra cũng ra r bạn ạ :))) –  Dark 06-06-16 09:57 PM

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