a) $x=\frac{-3}{8}-\frac{1}{6}=\frac{-13}{24}$b) <=> $\frac{5}{8}x=\frac{3}{4}$ <=> $x=\frac{6}{5}$
c) <=>$\left| {\frac{3}{4}-x} \right|=\frac{17}{12}$
<=> $\frac{3}{4}-x=\frac{17}{12}$ hoặc $\frac{3}{4}-x=\frac{-17}{12}$
<=> $x=\frac{-2}{3}$ hoặc $x=\frac{13}{6}$
d) <=> $(2x-\frac{9}{2}).\frac{4}{3}=\frac{4}{3}$
<=> $2x-\frac{9}{2}=1$
<=> $2x=\frac{11}{2}$ <=> $x=\frac{11}{4}$