$\cos x=\frac{1}{3} \Rightarrow \cos^2x=\frac{1}{9}\Rightarrow \sin^2x=\frac{8}{9}$Do $0<x<\frac{\pi}{2} \Rightarrow \sin x>0 \Rightarrow \sin x=\frac{2\sqrt{2}}{3}$
$\tan x=\frac{\sin x}{\cos x}=2\sqrt{2}$
$\cot x=\frac{1}{\tan x}=\frac{1}{2\sqrt{2}}$