Tính giá trị biểu thức sau một cách hợp lí:

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  .





   ; 

A=7/19 . (8/11 + 3/11) +12/19     ((A.B + A.C = A( B+C))

A= 7/19 .1 + 12/19 = 1

   

B= 5/9 . (7/13 + 9/13 - 3/13)        ( Tương tự câu a )

B= 5/9 .1 = 5/9

  

C= (67/111 + 2/33 - 15/117 ) .(4/12 - 3/ 12 - 1/12)    (  A.0 = 0 nên k cần tính vế đứng trước)

C=(67/111 + 2/33 - 15/117) . 0 = 0

CÓ J SAI SÓT MONG MN BỎ QUA ^^                                                                                                jin lion

Jin mụi đã trở lại :D –  ๖ۣۜJinღ๖ۣۜKaido 14-03-16 05:20 PM
$A=\frac{7.8}{19.11}+\frac{7.3}{19.11}+\frac{12.11}{19.11}=\frac{7(8+3)+12.11}{19.11}=\frac{11(7+12)}{19.11}=1.$
$B=\frac{5.7+5.9-5.3}{9.13}=\frac{5(7+9-3)}{9.13}=\frac{5.13}{9.13}=\frac{5}{9}.$
Có: $\frac{1}{3}-\frac{1}{4}-\frac{1}{12}=\frac{4-3-1}{12}=0.$
$\Rightarrow C=\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).0=0.$
ừ :)))))))))) –  111aze 14-03-16 03:47 PM
anh có rảnh không ? qua bên lý giúp em mấy bài vừa đăng –  Hàn Thiên Dii 14-03-16 03:46 PM
A=$\frac{7}{19}$($\frac{8}{11}$+$\frac{3}{11}$)+$\frac{12}{19}$=$\frac{7}{19}$+$\frac{12}{19}$=1
B=$\frac{5}{9}$($\frac{7}{13}$+$\frac{9}{13}$-$\frac{3}{13}$)=$\frac{5}{9}$
C=(...)($\frac{1}{12}$-$\frac{1}{12}$)=0

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