cho hình thang OABC ( OA//BC ) có Diện tích OABC =6. Điểm A(-1,2). Đỉnh B và C lần lượt thuộc d1: x+y+1=0 ; d2: 3x+y+2=0. Tìm tọa độ điểm C;B
có đưa giải cho mình –  Lionel Messi 10-03-16 07:11 PM
cần giải k bạn –  nguyenquangtruonghktcute 10-03-16 06:59 PM
OA: 2x+y=0
OA//BC$\Rightarrow$BC:2x+y+m=0(m$\neq$0)
B=d1$\cap$BC$\Rightarrow$B(1-m;m-2)
C=d2$\cap$BC$\Rightarrow$C(m-2;4-3m)
S OABC=$\frac{1}{2}$(OA+BC).d(O,BC)
$\Leftrightarrow$$\frac{1}{2}$.$\left[ {\sqrt{(-1)^{2}+2^{2}}+\sqrt{(2m-3)^{2}+(4m-6)^{2}}} \right]$.$\frac{\left| {m} \right|}{\sqrt{2^{2}+1}}$=6
$\Leftrightarrow$($\left| {2m-3} \right|$+1).$\left| {m} \right|$=12
$\Leftrightarrow$m=1 - $\sqrt{7}$ or m=3
$\Rightarrow$B($\sqrt{7}$;-1-$\sqrt{7}$)&C(-1-$\sqrt{7}$;1+3$\sqrt{7}$)
or B(-2;1)&C(1;-5)
Được:D:D –  Lionel Messi 10-03-16 08:46 PM
OA: 2x+y=0
BC:2x+y+m=0(m0)
B=d1BCB(1-m;m-2)
C=d2BCC(m-2;4-3m)
S OABC=12(OA+BC).d(O,BC)
12.[(1)2+22+(2m3)2+(4m6)2].|m|22+1=6
(|2m3|+1).|m|=12
m=1 - 7 or m=3
B(7;-1-7)&C(-1-7;1+37)
or B(-2;1)&C(1;-5)
ê tao bảo này –  Lionel Messi 10-03-16 08:55 PM
khác tí nào không xem đi –  Lionel Messi 10-03-16 08:55 PM
chắc j bn ấy đã copy –  Bloody's Rose 10-03-16 08:54 PM
đi coppy. Nhục lắm –  Lionel Messi 10-03-16 08:51 PM

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