đốt cháy hoàn toàn 2,3g 1 hợp chất bằng khí oxi sau phản ứng thu được 2,24 lít CO2 đktc và 2,7 g nước a, xđ thành phần định tính các nguyên tố trong hợp chất b, tính khối lượng từng nguyên tố trong 2,3g hợp chất trên

nhưg ko ai lm hộ tớ :( –  kimtaerim123 06-03-16 09:34 AM
đăng bên hóa bn ơi –  thánh FA 06-03-16 09:33 AM
a,nCO2=0,1 nên nC=0,1 mol
nH2O=0,15 nên nH=0,15.2=0,3 mol
suy ra nO=(2,3-0,1.12-0,3)/16=0,05 mol
nên trong hc có H,C,O
b,mC=0,1.12=1,2g
mH=0,3.1=0,3g
mO=2,3-1,2-0,3=0,8g

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