cho 3.1g p (phot pho) cháy trong 4.48 lít khí oxi ở đktc .hỏi a/ viết ptpư    b/tính số dư,chất nào dư                                                                                                           c/ tính khối lượng sản phẩm
@@ đăng ở đây sai chỗ r bn ơi,sang hóa mà đăng –  ๖ۣۜTQT☾♋☽ 03-02-16 03:31 PM
a)4P+5O2=2P2O5

a) 4P+5O2=2P2O5

b) Theo đề: nP=3,1:31=0,1(mol);nO2=4,48:22,4=0,2(mol)

Từ đề bài và pt có : $0,1/4<0,2/5=>O2

Theo pt: nO2=5/4.nP=5/4.0,1=0,125

n2dư=0,20,125=0,075=>mO2dư=0,075.32=2,4(g)

c) Theo pt: nP2O5=1/2.nP=1/2.0,1=0,05(mol)

mP2O5=0,05.142=7,1(g)

nhu the nghia la sao ? –  B4.THĐ 04-02-16 11:33 AM
em nên đặt công thức gõ trong cặp dấu $$ nhak –  ๖ۣۜJinღ๖ۣۜKaido 03-02-16 11:52 PM

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