Giải các phương trình sau:
a) x4 + 7x3 + 11x2 + 1 = 0 
b) (x + 1)(x + 3)(x + 5)(x + 7) = 9
c) x4 + (x – 1)(x2 – 2x + 2) = 0
d) (x + 3)4 + (x + 5)4 = 2
cái câu c phân tích ra = x^4 x^3-3x^2 4x-2nhưng e quên cách tìm nghiệm nên ko phân tick đc câu 1 và 3 –  Ghost rider 25-10-15 06:04 PM
$b,(x+1)(x+3)(x+5)(x+7)=9$
  $ [(x+1)(x+9)][(x+3)(x+5)]-9=0$
   $(x^2+8x+7)(x^2+8x+15)-9=0$
đặt $x^2+8x+7=x$
ta có$:x^2+2x-9=0$

suy ra$:(x-1)(x+9)=0$
từ đó tính ra $x$
vãi cả đặt ẩn phụ giống ẩn cần tìm :3 –  ๖ۣۜPXM๖ۣۜMinh4212♓ 25-10-15 10:20 PM
xorry nha anh,cái bậc 4 e hok r nhưng quên tìm nghiệm –  Ghost rider 25-10-15 05:55 PM

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