Cho ax3=by3=cz31x+1y+1z=1
            Chứng minh rằng 3ax2+by2+cz2=3a+3b+3c
Đặt: ax3+by3+cz3=m3(m thuộc R)
     ax2=m3x;by2=m3y;cz2=m3z
 ax2+by2+cz2=m3(1x+1y+1z)=m3.1=m3
  3ax2+by2+cz2=3m3=m   (1)
 Có: ax3=m3a=m3x33a=3m3x3=mx
 Chứng minh tương tự: 3b=my;3c=mz
3a+3b+3c=m(1x+1y+1z)=m.1=m   (2)
 Từ (1) và (2) Điều phải chứng minh.
  Đúng thì đánh dấu tích nhá.
cảm ơn bạn rất nhiều nhớ vote cho tui vs –  Sea Dragon 08-09-15 09:15 PM
Ta có :
ax2=by3x=cz3x2ax2=by3x+cz3x
Tương tự ta có :
2by2=ax3y+cz3y
2cz3=ax3z+by3z
Cộng vế theo vế, ta có 2(ax2+by2+cz2)=cz3(1x+1y)+by3(1x+1z)+ax3(1y+1z)()
ax3=by3=cz3 nên từ ()2(ax2+by2+cz2)=ax3(1x+1y+1x+1z+1y+1z)
2(ax2+by2+cz2)=2ax3(1x+1y+1z)=2ax3
ax2+by2+cz2=ax33ax2+by2+cz2=x.3a
1x.3ax2+by2+cz2=3a
Tương tự ta có
1y.3ax2+by2+cz2=3b;1c.3ax2+by2+cz2=3c
cộng vế theo vế 3ax2+by2+cz2(1x+1y+1z)=3a+3b+3c
đpcm
cảm ơn bạn rất nhiều nhớ vote cho tui vs –  Sea Dragon 08-09-15 09:16 PM
đánh mệt quá ai đi ngang cho xin 1 cái vote up –  tran85295 08-09-15 07:26 PM

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