$\begin{cases}2y^3+y+2x\sqrt{1-x}=3\sqrt{1-x} \\ \sqrt{2x^2+1}+y=4+\sqrt{x+4} \end{cases}$
bài này dùng đặc trưng của hàm để giải

$1<=>2y^3+y=2(1-x)\sqrt{1-x}+\sqrt{1-x}$

dùng hàm số để suy ra $y=\sqrt{1-x}$ rồi thay vào 2 nhé
mới lớp 10 thôi.hĩ –  tuyettl.01 11-01-15 10:47 PM
(1) $2y^3+y=(2-2x-2)\sqrt{1-x}+3\sqrt{1-x}$
<=> $2y^3+y=2(1-x)\sqrt{1-x}-2\sqrt{1-x}+3\sqrt{1-x}$
<=> $2y^3+y=2\sqrt{(1-x)^3}+\sqrt{1-x}$
=> $y= \sqrt{1-x}$ ( nếu muốn biết tại sao lại thê thì đặt $\sqrt{1-x}=a$ khắc thấy)

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