trong mặt phẳng tọa dộ Oxy cho hình vuông $ABCD$ voi $M, N$ lan lượt la trung điểm $AB, BC. H$ la chân đường cao kẻ từ B xuông $CM$. tìm tọa độ các đỉnh hình vuông $ABCD$ biết $N(-1;-5/2), H(-1;0)$ va H nằm trên d: $x - y -4=0.$
H nằm trên d sao tọa độ điểm H không thỏa mẵn pt x-y-4=0 ? –  Vân Nguyễn 10-11-14 10:35 PM

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