GIẢI PHƯƠNG TRÌNH
$\sqrt{x-1}-\sqrt{5x-1}=\sqrt{3x-2}$
Điều kiện để pt xác định là $x\geq 1$. Với điều kiện này thì $x<5x$ do đó $\sqrt{x-1}<\sqrt{5x-1}$ suy ra vế trái của pt là số âm, còn vế phải không âm nên pt vô nghiệm

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