giải phương trình
a.$\sqrt{3x^2 - 9x +1 }=|x-2|$
b.$\sqrt{4 -\sqrt{1-x}} = \sqrt{2-x }$
c.$\sqrt[3]{x+1} + \sqrt[3]{x-1}=\sqrt[3]{5x}$
d.$x^3 -3x^2 + 2\sqrt{(x+2)^2}-6x=0$
e.$\sqrt{5x^2 - 14x +9 } - \sqrt{x^2 - x - 20} = 5\sqrt{x - 1}$

$\sqrt[3]{x+1}+\sqrt[3]{x-1}=\sqrt[3]{5x}$


$<=>x+1+x-1+3\sqrt[3]{(x+1)(x-1)}(\sqrt[3]{x+1}+\sqrt[3]{x-1})=5x$


$<=>3\sqrt[3]{5x(x+1)(x-1)}=3x$


$<=>\sqrt[3]{5x(x+1)(x-1)}=x$



$<=>5x(x+1)(x-1)=x^3$


$<=>5x^3-2x=x^3$


$<=>2x^3-x=0$


$XONG$

đúng thì nhấn V và vote up cho mk nhé. –  ♥♥♥ Panda Sơkiu Panda Mập ♥♥♥ 04-02-14 12:01 PM

tự giải điểu kiện nhé


$\sqrt{4-\sqrt{1-x}}=\sqrt{2-x}$

$<=>4-\sqrt{1-x}=2-x$

$<=>x+2=\sqrt{1-x}$(dk để vt $\ge0$)

$<=>x^2+4x+4=1-x$

$<=>x^2+5x+3=0$

$XONG$
đúng thì nhấn v và vote up cho mk nhé. –  ♥♥♥ Panda Sơkiu Panda Mập ♥♥♥ 04-02-14 12:02 PM
$\sqrt{3x^2-9x+1}=\left| {x-2} \right|$(dk tự làm nhé)

$<=>3x^2-9x+1=(x-2)^2$

$<=>3x^2-9x+1=x^2-4x+4$

$<=>2x^2-5x-3=0$

$XONG$
đúng thì nhấn v và vote up cho mk nhé. –  ♥♥♥ Panda Sơkiu Panda Mập ♥♥♥ 04-02-14 12:02 PM

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