$A= 0 1 2 3 4 5 6 7$. Từ $A$ có thể lập đc ? số TN có các chữ số khác nhau và
a) có $3$ cs và tổng các cs ko quá $15$
b) có $4$ cs mà $2$ cs $1$ và $6$ ko đứng cạnh nhau
cau a nek:
+)Chon tuy u so co 3 chu so khac nhau co:$A^3_8-A^2_7=294 $ so.
+)Chon so co 3 chu so ma tong cac chu so lon hon $15:$
goi so can tim co dang:$\overline{abc}\Rightarrow (a;b;c)={(3;6;7);(4;6;7);(5;6;7)}$
$\Rightarrow $ co $3.A^3_3=18$ so co dang $\overline{abc}      $ ma   $(a+b+c>15)$
Vay co :$294-18=276$ so tm dkbt


Hjnh nhu la` dug' rui...... –  keobacha138 27-11-13 12:59 PM
k biet coa dung hay k T_T –  Gió! 25-11-13 09:10 PM

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