tìm ngiệm nguyên của phương trình
y2=x2+x+1
$\Leftrightarrow 4x^2 +4x +4 -4y^2=0$

$\Leftrightarrow (2x+1)^2 -(2y)^2 =-4$

$\Leftrightarrow (2x+2y+1)(2x-2y+1)=-4 =-1.4 =-4.1=-2.2 =2.(-2)$

Xét mấy trường hợp đó là ra

$(x=0;\ y=\pm 1);\ (x=-1;\ y=\pm 1)$
cách này hay đấy nhỉ –  ♥♥♥ Panda Sơkiu Panda Mập ♥♥♥ 22-11-13 12:41 PM

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