Tam giác ABC cân tại A góc A = 40độ. AH vuông góc với BC . E thuộc AH,F thuộc AC 
góc EBA =FBC=30 độ. Tam giác đều AFI (I thuộc nửa mặt phẳng bờ AC không có điểm B.)
Chứng minh: I;E;B thẳng hàng.

bị xóa vì bị trùng bởi Đức Vỹ 27-10-13 03:10 PM

Câu hỏi này có nội dung hoàn toàn trùng với câu hỏi đã có.

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