$sin^{10}x+cos^{10}=\frac{29}{16}cos^42x$ 

VT = (sin^4 x + cos^4 x)(sin^6 x + cos^6x) -sin^4 x . cos^6 x . - sin^6 x . cos^4 x 

= (1 - 2 sin^2 x cos^2 x)(1 - 3 sin^2 x cos^2 x). - sin^4 x. cos^4 x

=1 - 5sin^2 x . cos^2 x + 5sin^4 x. cos^4 x

dùng công thức biến đổi phần sin.cos thành sin 2x làphần sau tự giải được rồi đấy


mà khi nào bạn chỉ mình cách gõ các công thức để tiện cho việc đưa lời giải nha. mình mới lên nên chưa biết cách dùng các công thức ở đây nên bạn thông cảm nha.

Bạn cần đăng nhập để có thể gửi đáp án

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