$ x^{2}_{1} + y^{2}_{1}-2x_{1}+4y_{1}-5=0$
$x^{2}_{2} + y^{2}_{2}-2x_{2}+4y_{2}-5=0$
$\left ( x_{1}-1 \right )^2+ y^{2}_{1}=(x_{2}-1)^2+y^{2}_{2}$
$(x_{1}-1)(x_{2}-1)+ y_{1}y_{2}=0$
4 cái đó là 1 hệ áh T.T –  kreities847 21-06-13 04:50 PM
co the chuyen no ve dang hinh hoc phang do –  Pooh 21-06-13 06:54 AM
chả hiểu , có 2 hệ hả em, nếu k phải thì 2 cái pt đầu liên quan j nhau? –  chaicolovenobita 21-06-13 06:32 AM

bị xóa vì bị trùng bởi Đức Vỹ 27-10-13 01:51 PM

Câu hỏi này có nội dung hoàn toàn trùng với câu hỏi đã có.

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