Dk $x\geq \frac{-1}{8}$
$pt<=> (x+1)-\sqrt{3x+1}+(2x+1)-\sqrt{8x+1}=0$
$<=>\frac{x^{2}-x}{x+1+\sqrt{3x+1}}+\frac{4(x^{2}-x)}{2x+1+\sqrt{8x+1}}=0$
$<=>(x^{2}-x)(\frac{1}{x+1+\sqrt{3x+1}}+\frac{4}{2x+1+\sqrt{8x+1}})=0$
$<=>x=0 hoac x=1 $ (do dk nen bieu thuc trong ngoac luon lon hon 0)