cho khối chóp S.ABC có hai mặt ABC và SBC là các tam giác đều cạnh a và SA=$\frac{_{a}\sqrt{3}}{2}$.Tính thể tích khối chóp theo a.
có ai giúp hộ mình toán hình pos trên ko –  nh0cmaimai 01-05-13 11:57 PM

Lay trung diem cua BC la M suy ra SM vuong vs BC do tam giac SBC deu
Cung co AM vuong vs BC do tam giac ABC deu
Tu do suy ra BC vuong (ASM) 
Tu S ha SH vuong AM vs H thuoc AM 
Do BC vuong (ASM) suy ra BC vuong SH
Vay SH vuong vs AM va BC suy ra SH vuong mp( ABC)
SH la duong cao 
Tinh SH thong qua dien tich tam giac (SAM) la tam giac deu do AS=AM=SM=a.can3/2
SH=3a/4
vay V=1/3.SH.dt(ABC)=can3.a^3/16
ta goi ra the thoi tuc la dung hinh ma –  thiensugacoi_95 02-05-13 01:28 AM
làm gì có điểm M và H bạn –  nh0cmaimai 02-05-13 12:34 AM
Dung thi vote ho nhe ^^ –  thiensugacoi_95 02-05-13 12:25 AM

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