$2^{x^{2}+x}-4.2^{x^{2}-x}-2^{2x}+4=0$    giai giup minh đi
oài, khó thế –  congiola_ktqd 07-01-13 08:59 PM
Đặt $a=2^{x^2-x},b=2^{2x}$
Phương trình đã cho trở thành $ab-4a-b+4=0\Leftrightarrow  (a-1)(b-4)=0$
suy ra $\begin{cases}a=1 \\ b=4 \end{cases} \Leftrightarrow \begin{cases} 2^{x^2-x}=1 \\ 2^{2x}=4 \end{cases}$
Suy ra $x=1$ hoặc $x=0$
chuẩn rồi ad! –  congiola_ktqd 07-01-13 08:59 PM

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